16m^2-5m=40m^2

Solution for 16m^2-5m=40m^2 equation:

16m^2-5m=40m^2

We move all terms to the left:

16m^2-5m-(40m^2)=0

determiningTheFunctionDomain
16m^2-40m^2-5m=0

We add all the numbers together, and all the variables

-24m^2-5m=0

a = -24; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-24)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-24}=\frac{0}{-48}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-24}=\frac{10}{-48}
=-5/24
$